45x^2+150x=0

Solution for 45x^2+150x=0 equation:

45x^2+150x=0

a = 45; b = 150; c = 0;
Δ = b2-4ac
Δ = 1502-4·45·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-150}{2*45}=\frac{-300}{90}
=-3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+150}{2*45}=\frac{0}{90}
=0
$